Solve the following:

(1 - Sin^{2}θ)(Sec^{2}θ)

This question was previously asked in

UPSSSC Chakbandi Lekhpal Official Paper 1 (Held on : 30 Sept 2019 Shift 1)

- 0
- 1
- Sinθ
- Cosθ

Option 2 : 1

**Given:**

(1 - Sin2θ)(Sec2θ)

**Formula used:**

Cos^{2}θ = 1 - Sin^{2}θ

Cosθ = 1/Secθ

**Calculation:**

According to the question, we have

(1 - Sin2θ)(Sec2θ)

⇒ Cos^{2}θ × (1/Cos^{2}θ)

⇒ 1

**∴ The value of (1 - Sin2θ)(Sec2θ) is 1. **

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